One hundred kilomoles of wet natural gas containing a mixture of methane (CH4) and ethane (C2H6) are combusted. The mole ratio of total carbon to total hydrogen in fuel is given as 13:50. Assuming complete combustion and 50% excess air entering the combustion chamber, compute for the following:
How much air in kmoles is entering the combustion chamber?
Percent of ethane in the fuel is?
How much water was formed?
Theoretical oxygen needed in kmoles is
Amount in kmoles of carbon dioxide found in the flue gas is
Percent of methane in the fuel is
Total number of kmoles in the flue gas is
What is the theoretical air needed in kmoles?
Comments
Leave a comment