Answer to Question #184586 in General Chemistry for omer

Question

How much energy is required to convert 12.00 g of ice at -5.00 °C to liquid water at 2.50 °C?

Answer 1

Converting $12.0g$ of ice to $0°C$

$=12.0\times 10=1200calories$

Converting to water at $2.5°C$

$=12.0g\times 2.5=30 calories$

Latent heat of vaporization of water $=537calories/g$

$=537\times 12=6444 calories$

Total heat of fission$=(1200+30+6444)=7674 calories$