The volume of a gas is 7.6 L when the temperature is 8.000C. If the temperature is increased to 22.00C without
changing the pressure, what is the new volume? (Look at significant figures!)
T1V1=T2V2T_1V_1=T_2V_2T1V1=T2V2
V2=T1V1T2V_2=\frac{T_1V_1}{T_2}V2=T2T1V1
V2=7.6×281295=7.2LV_2=\frac{7.6×281}{295}=7.2LV2=2957.6×281=7.2L
Ans= 7.2L
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