Answer to Question #184563 in General Chemistry for Topher

Question

Liquid bromine and gaseous fluorine can undergo a synthesis reaction in the presence of heat

to produce bromine pentafluoride, a covalent compound. How many molecules of bromine react

with 1.11 X 1020 molecules of fluorine?

Answer 1

$Br + 5F → BrF_5$

Ratio 1:5 this implies that 1 mole of bromine reacts with 5 moles of fluorine to produce 1 mole of Bromine pentafluoride

Therefore the molecules of fluorine which will react with bromine is equal to

1.11×1020×5 = 5.55×1020 Molecules