Question #184420

Find the mass of the following gas

175 mL CO2 at 0.711 atm and -3 degrees C


1
Expert's answer
2021-04-23T07:31:37-0400

Mass=UnknownMass= Unknown

Volume=175mlVolume=175ml =0.175L=0.175L

Pressure=0.711atmPressure=0.711atm

Temperature=276kTemperature=276k

0.08206L.atm/K.mol0.08206L.atm/K.mol

From the equation;

Pv=nRTPv=nRT

n=n= PvRTPv\over RT

== (0.711×0.175)(0.08206L.atm/K.mol)(0.711\times 0.175)\over (0.08206 L.atm/K.mol)

=5.593×103=5.593\times 10^{-3}

Mass to grams

=5.595×103mol×12.0g/mol=5.595\times 10^{-3}mol\times 12.0g/mol

=0.067g=0.067g


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