Find the mass of the following gas
175 mL CO2 at 0.711 atm and -3 degrees C
Mass=UnknownMass= UnknownMass=Unknown
Volume=175mlVolume=175mlVolume=175ml =0.175L=0.175L=0.175L
Pressure=0.711atmPressure=0.711atmPressure=0.711atm
Temperature=276kTemperature=276kTemperature=276k
0.08206L.atm/K.mol0.08206L.atm/K.mol0.08206L.atm/K.mol
From the equation;
Pv=nRTPv=nRTPv=nRT
n=n=n= PvRTPv\over RTRTPv
=== (0.711×0.175)(0.08206L.atm/K.mol)(0.711\times 0.175)\over (0.08206 L.atm/K.mol)(0.08206L.atm/K.mol)(0.711×0.175)
=5.593×10−3=5.593\times 10^{-3}=5.593×10−3
Mass to grams
=5.595×10−3mol×12.0g/mol=5.595\times 10^{-3}mol\times 12.0g/mol=5.595×10−3mol×12.0g/mol
=0.067g=0.067g=0.067g
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