Question #184414

In a simple firing testing, 1.03 g of an explosive material, which has a power index of 211.71

and can produce a gas product up to 9.2 dm3 per gram, was packed in a handgun ammunition

cartridge and triggered to detonate to propel a projectile weighed 2 g out of the barrel. The

efficiency of the energy transferred from the explosion to the projectile is 13 %. Calculate the

propelled bullet velocity in m/s if the heat evolved and gas volume produced in a detonation of

per gram picric acid is 3150 J/g and 0.831 dm3


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1
Expert's answer
2021-04-29T07:25:27-0400

Energy produced per gram of picric acid, Qpicric=3150 J/gQ_{picric}=3150\space J/g

Volume of picric acid, Vpicric=0.831 dm3V_{picric}=0.831\space dm^3

Power Index =211.71=211.71

Let energy produced per gram of explosive material be QQ

Volume of explosive material per gram =9.2 dm3/g=9.2\space dm^3/g

Volume of explosive material, (V)(V) for 1.03 g =9.2×1.03=9.476 dm3=9.2\times1.03=9.476\space dm^3

Power Index =QVQpicricVpicric=\dfrac{QV}{Q_{picric}V_{picric}}


Q=211.71×3150×0.8319.476Q=\dfrac{211.71\times3150\times0.831}{9.476}

Q=58482.765 J/gQ=58482.765\space J/g

Energy of Explosion =58482.765×1.03=60237.247 J=58482.765\times1.03=60237.247\space J

Efficiency of energy transferred from the explosion to the projectile =13%=13\%

Energy of projectile =0.13×60237.247=7830.84 J=0.13\times60237.247=7830.84\space J

Mass of projectile, m=2 g=2×103 kgm=2\space g=2\times10^{-3}\space kg

Let velocity of projectile be vv

12mv2=7830.84\dfrac{1}{2}mv^2=7830.84

v=2×7830.842×103v=\sqrt{\dfrac{2\times7830.84}{2\times10^{-3}}}

v=2798.36 m/sv=2798.36\space m/s


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30.04.21, 14:54

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29.04.21, 20:02

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