Question

Lead (IV) oxide is an important component of lead-acid car batteries. What volume of a 2.00mol/L solution of nitric acid is sufficient to react with 105g of lead (IV) oxide?

Answer 1

2PbO₂ + 4HNO₃ → 2Pb(NO₃)₂ + 2H₂O + O.

$Moles (PbO_2)= \frac{105}{239.2}=0.44moles$

$Moles (HNO_3)= \frac{0.44×4}{2}=0.88moles$

$Volume = \frac{0.88}{2.00}=0.44L$