Answer to Question #184309 in General Chemistry for dsafd

Question

Which of the following is the correct mathematical expression to use to calculate the pH of a 0.10M aqueous KOH solution at 25°C? Explain

• pH = 14.00 + log(0.10)

• pH = −log(0.10)

• pH = 14.00 − log(0.10)

• pH = log(0.10)

Answer 1

We know that

$P_H =-log[H^+]$

$P_{OH} = -log[OH^-]$

$P_H + P_{OH}=14$

By using this

We got

$\boxed{pH = 14.00 − log(0.10)}Answer$