Answer to Question #184359 in General Chemistry for Isaiah

Question

A standard airbag has 130.0 g of sodium azide (NaN3). How many grams of nitrogen (N2) can be produced from this amount based 2 NaN3(s) → 2 Na(s) + 3 N2(g)

Answer 1

2NaN₃----> 2Na + 3N2

Molar mass of sodium azide (NaN₃) = 23+(14*3) =65

Molar mass of nitrogen (N₂) = 14*2 = 28

Since 2 moles of sodium azide produces 3 moles of nitrogen gas.

Using mass mole relationship

no of moles = mass/molar mass

Mass = no of moles x molar mass

∴ 2 (65) ---------------> 3(28)

∴ 130 g ---------------->?

By cross multiplying we have

Mass of nitrogen gas produced =(130 x 84)/130

= 84

∴ the mass of nitrogen gas produced = 84g