Question

AN UNKNOWN METAL SAMPLE WITH A MASS OF 9.2 G IS HEATED TO A
TEMPERATURE 52OC, AND DROPPED INTO 18.8G OF WATER WITH A TEMPERATURE
OF 30OC. THE FINAL TEMPERATURE OF THE SYSTEM IS 31OC. GIVEN THAT THE
SPECIFIC HEAT OF WATER IS 4.2 J/G C, WHAT IS THE SPECIFIC HEAT OF
THE UNKNOWN METAL?

Accepted Answer

Mw = 18.8

= 9.2

Tn= 52°C = 30°C

Tf = 30°C

X = 18.8 (31-30) × 4.2/(9.2(31-52)

= 0.409J

Question #182109

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