An unknown metal sample with a mass of 9.2 g is heated to a temperature 52oC, and dropped into 18.8g of water with a temperature of 30oC. The final temperature of the system is 31oC. Given that the specific heat of water is 4.2 J/g C, what is the specific heat of the unknown metal?
Mw = 18.8
= 9.2
Tn= 52°C = 30°C
Tf = 30°C
X = 18.8 (31-30) × 4.2/(9.2(31-52)
= 0.409J
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