A container is filled with an ideal gas to a pressure of 11.0 atm at 0oC.
a. What will be the pressure in the container if it is heated to 45o C?
From the ideal gas equation;
P1V1T1P1V1\over T1T1P1V1 === P2V2T2P2V2\over T2T2P2V2
P1=11.0atmP1=11.0atmP1=11.0atm
T1=(0+273K)T1=(0+273K)T1=(0+273K)
V1=22.4L(STP)V1=22.4L(STP )V1=22.4L(STP)
P2=unknownP2=unknownP2=unknown
T2=(273+45)T2=(273+45)T2=(273+45)
V2=22.4L(STP)V2=22.4L(STP)V2=22.4L(STP)
Applying the formula;
P2=P2=P2= P1V1T2V2T1P1V1T2\over V2T1V2T1P1V1T2
P2=P2=P2= 11.0×22.4×31822.4×27311.0\times \cancel {22.4}\times 318\over \cancel{22.4}\times 27322.4×27311.0×22.4×318 =12.81atm=12.81atm=12.81atm
∴P2=12.81atm\therefore P2=12.81atm∴P2=12.81atm
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