Aluminum will react with oxygen to form aluminum oxide. It takes 2.00 L of pure oxygen gas at STP to react completely with a certain sample of aluminum. What is the mass of aluminum reacted?
Find moles of O2 and then from the balanced equation find moles and mass of Al.
PV = nRT
"n =\\frac{ PV}{RT} =\\frac{ (1 atm)(2.00 L)}{(0.0821 Latm\/Kmol)(273 K)}"
"n = moles ...O_2 = 0.0892 moles"
"moles Al = 0.0892 moles (O_2)\u00d7\\frac{ 4 moles( Al)}{3 }"
moles O2 = 0.119 moles Al
mass Al = 0.119 moles x 26.98 g/mole = 3.21 g of Al
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