Nitrogen gas reacts with hydrogen gas to form ammonia gas. Given that the standard entropies of nitrogen, hydrogen and ammonia gases are 192, 131 and 193 JK-¹mol-¹ respectively, calculate the standard entropy change for the reaction
1/2 N2 + 3/2 H2 > NH3
∆ S ° = ∆S° (product) - ∆S° (Reactant)
∆S° = 192- (1/2 ×191.5 + 3/2 × 130.5)
∆S° = 192.6 - (95.75 + 195.75)
∆S° = 192.6 - 291.5 = -98.9 J/mol -k
Therefore ∆S° of the formation of Ammonia is -98.9 J/mol -k
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