A solution contains 19 g of NaCl in a total volume of 325 mL. What is the NaCl concentration of the solution in g/L, % w/v and mol/L?
Molar mass of NaCL = 58.44
Moles = 1958.44=0.3251\frac{19}{58.44}=0.325158.4419=0.3251
325 mL = 0.325L
Morality = 0.32510.325=1.0003g/L\frac{0.3251}{0.325}=1.0003 g/L0.3250.3251=1.0003g/L
1.0003×100= 100.03%w/v or 1.0003mol/L
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