In January 2025
Answer to Question #175072 in General Chemistry for mobina
75.4 g of Na2S, sodium sulphide is mixed with water to form 4.0 L of solution. What is the concentration of the sodium ions, Na+1 in the solution? Hint: write out dissociation reaction
Molar concentration = (mass/volume) ÷ molar mass
= (75.4/4) ÷ 78
= 0.242M
Na2S = 2Na + S
Concentration of Na = 2 × 0.242M = 0.484M
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