Question

41-45. Calculate the ∆H0rxn for the reaction C (graphite) + 2H2(g)→CH4(g) From the following enthalpy changes:

C(graphite) + O2(g)→CO2(g)

2H2(g) + O2(g)→2H20(l)

CH4(g) + 2O2(g)→CO2(g) + 2H2O(l)

∆ = -393.5kJ ∆ = -571.6kJ ∆ = -890.4kJ

Answer 1

To get the $\Delta H$ ;

$=(-393.5+-571.6 - (- 890))kJ/mol.$

$=-75.1kJ$