calculate the solubility of zns in 1 f acetic acid
Molar Mass of ZnS = 97.474 g/mol
Molar Mass of CH3COOH = 60.052
1f = N /60.052
N = 60.052× 1 = 60.052
= 60.052 + 97.474 = 157.526
= (157.526/60.052) × 100g
= 262.32g/100g
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