Gypsum is hydrated calcium sulphate (CaSO4.xH2O). 5.65 g of anhydrous calcium sulphate is obtained by heating 7.15 g of gypsum. Determine the empirical formula of gypsum.
solve this
write out the equation first,assume that the number of water is x
CaSO4.xH2O(136+18x)=CaSO4(136)+xH2O(18x)
The difference between anhydrous calcium sulphate and x water is
7.15- 5.65 = 1.5g
Therefore the mass of water is 1.5g
136/5.65=18x/5.0
5.65g divided by 136g/mol equals to 0.042mol
7.15g divided by 0.042mol equals to 172.1 g/mol
172.1g/mol minus 136g/mol equals to 36.1 g/mol
36.1g/mol divided by 18g/mol equals to 2
Therefore empirical formula of gypsum is CaSO4·2H2O
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