How many moles of hydrogen are contained in 5.00 L at 0degrees Celsius and 1 atm?
n=PVRTn=\frac {PV} {RT}n=RTPV
n=1atm×5.00L0.0821×273n=\frac {1 atm×5.00L} {0.0821×273}n=0.0821×2731atm×5.00L
n=0.223molesn=0.223molesn=0.223moles
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