Ans:- Molecular mass of CH3COOH is 60 molg
Now find the moles of acetic acid
⇒ moles of acetic acid=molecularmassgivenmass
⇒ 6050=0.833mol
Therefore Molality=massofsolventin(gm)no.ofmolesofsolute×1000
⇒ molality of acetic acid=9500.833×1000=0.8771m
Therefore molality of acetic acid in ethanol is 0.8771m
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