Answer to Question #168398 in General Chemistry for Dawson

Question

Copper(I) oxide can be oxidized to copper(II) oxide:

 

Cu₂O(s) + 1/2 O₂(g) → 2 CuO(s)

ΔH⁰_rxn = -146.0 kJ

Given ΔH⁰_f of Cu₂O(s) = −168.6 kJ/mol, find ΔH⁰_f of CuO(s).

Answer 1

$ΔH0f=ΔH0rxn-ΔH0f$

=-146--168.6

= 22.6kJ/mol