Answer to Question #168398 in General Chemistry for Dawson

Question #168398

Copper(I) oxide can be oxidized to copper(II) oxide:

 

Cu2O(s) + 1/2 O2(g) → 2 CuO(s)

ΔH0rxn = -146.0 kJ

Given ΔH0f of Cu2O(s) = −168.6 kJ/mol, find ΔH0f of CuO(s).

1
Expert's answer
2021-03-05T03:27:58-0500

"\u0394H0f=\u0394H0rxn-\u0394H0f"

=-146--168.6

= 22.6kJ/mol


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