How many liters of chromium are needed to react with an excess of CuSO4 to produce 7.50 moles Cu?
Cr + CuSO4 = CrSO4 + Cu
According to the equation
n(Cu) = n(Cr) = 7.5 moles
V(Cr) = n*Vm = 7.5mol*22.4L/mol = 168 L
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