Answer to Question #156725 in General Chemistry for samantha atwell

Question

If 5.78 moles of calcium nitrite reacts with excess cesium, how many moles of cesium nitrite can be made?

Answer 1

$Ca(NO_3)_2 + 2Cs \to Ca + 2CsNO_3$

1 mole of Calcium Nitrate reacts with Caesium to form 2 moles of Caesium Nitrate.

This means that;

1 mole of Calcium Nitrate = 2 moles of Caesium Nitrate

Therefore, 5.78 moles of Calcium Nitrate = 11.56 (5.78 × 2) moles of Caesium Nitrate

11.56 moles of cesium nitrite can be made.