nKClO3=nKCl; "{\\frac {m(KClO3)} {M(KClO3)}=\\frac {m(KCl)} {M(KCl)}}" "m(KCl)=\\frac {m(KClO3) \u2217 M(KCl)} {M(KClO3)}" ; m(KCl) = 2.433 (grams).
SOLUTION: 2.433 grams
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment