Question

Calculate the root mean square velocity, in m/s, of carbon dioxide molecules at 100.0ºC.

Answer 1

Molar mass of CO2,

mm = 44.01g/mol

= 0.04401 Kg/mol

T= 100.0 C

= (100.0+273) K

= 373 K

vrms = sqrt (3$\times$ R$\times$ $\frac{T}{M}$ )

here : T is temperature in Kelvin

and M is molar mass in Kg/mol

So,

vrms = sqrt(3$\times$ 8.314$\times$ $\frac{373.0}{0.04401}$ )

= 459.8 m/s

Answer: 459.8 m/s