Calculate the volume necessary to react in 0.750 N Potassium hydroxide reacts with 23.2 ml of 0.385 N sulphuric acid.
M1V1 = M2V2
M1 = 0.750N , V1 = ? , M2 = 0.385N ,V2 = 23.2ml
0.750N×V1 = 0.385N×23.2ml
0.750N × V1 = 8.932 Nml
V1 = 8.932Nml/0.750N
V1 = 11.90 ml
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