1.calculate the mass of sulphuric(vI) acid in 250cm³ of solution whose concentration is 0.25mole dm-3
2.calculate the:
(A) number of moles present 25cm³ of a 0.2M sodium hydroxide solution.
(B)mass in grams present 25cm³ of a 0.2M
(Na=23,O=16,H=1).
3.calculate the number of moles of sodium chloride in 500cm3 of 3M sodium chloride solution.
4.calculate the mass of calcium chloride(CaCI2,) required to make one litre of 0.2M calcium chloride solution
5.when 34.8 grams of pottasium sulphate (K2SO4,) were dissolved in 500cm³ distilled water. Calculate:
(i) The concentration of potassium sulphate in g/litre
(ii) The molarity of the solution.(K=39.0,S=32.0,O=16.0
Mole = volume / Molar volume
= O.25dm3/0.25moledm-3
= 1.00mol
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