Calculate the molar concentration of the acid in 24.3 ml HNO3 are neutralized by 37.2 ml of 1.25 M KOH.
Molar concentration
m1v1 = m2v2
m1 = ? , v1 = 24.3ml , m2 = 1.25M , v2 = 37.2ml
m1 × 24.3ml = 1.25M × 37.2ml
m1 = "\\frac{1.25M\u00d737.2ml}{24.3ml}"
m1 = 1.9135M
Molar concentration of the acid is 1.9135M
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