Answer to Question #154696 in General Chemistry for Phyroe

Question

Calculate the molar concentration of the acid in 35 ml of HCl are neutralized by 42.5 ml of 0.250 M NaOH.

Answer 1

Molar concentration

m₁v₁ = m₂v₂

m₁ = ? , v₁ = 35ml , m₂ = 0.250M , v₂ = 42.5ml

m₁ × 35ml = 0.250M × 42.5ml

m₁ = $\frac{0.250M×42.5ml}{35ml}$

m₁ = 0.3035M

Molar concentration of acid is 0.3035M