Question

What volume of a 0.75 mol/L solution of aluminum iodide contains in 4.5 x 10-2 moles?

Answer 1

$Molarity=$ $Moles of solute\over Volume of Solution$

In finding the volume of the solution of Aluminum iodide;

$Volume=$ $Moles of solute\over Molarity of the solution$

$Number of moles=4.5\times 10^{-2}$

$Molarity=0.75mol/L$

$\therefore Volume =$ $0.45\times 1000\over0.75$ $=60ml$

The volume of the solution $=60 ml$