Question

What volume of a 0.75 mol/L solution of aluminum iodide contains in 4.5 x 10-2 moles?

Answer 1

Proportion:

0.75 mol – 1000 mL

0.045 mol – x

$x = \frac{0.045 \times 1000}{0.75} = 60 \;mL$

Answer: 60 mL