Given the wavelength of electromagnetic line emitted by Hydrogen lamp, λ = 6.77 x 10^-7 m
As we know if frequency of electromagnetic radiation = ν s^-1
And velocity of it = C m/s
Then, C = v × λ
Or, v = C/λ
As, velocity of light, C = 3 × 10^8 m/s
So,
v = ( 3 × 10^8 m/s ) / ( 6.77 x 10^-7 m )
=4.431 × 10^14 s^-1
Hence the frequency of the given line
= 4.431 × 10^14 s^-1
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