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Answer to Question #139166 in General Chemistry for D
Question #139166
Calculate the pH of a 0.021 M NaCN solution. [Kb(NaCN) = 5.0 ´ 10-5]
Expert's answer
Since , NaCN is formed by a mixture of a strong base and weak acid we need Ka of HCN to calculate the pH
I am just solving it using the Kb
Ph = 7+0.5Pkb-0.5logC
Ph= 7 - 0.5logKb -0.5log0.021
Ph =7 + 2.15 +0.83
= 9.98
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