Answer to Question #139137 in General Chemistry for Priyanka Mishra

Question #139137

A 65.0g sample of mg sulfide is found to contain 31.5g of mg. What is the percent by mass of sulfur in the compound?

Expert's answer

m(MgS) = 65.0 g

∆m = 65.0 — 31.5 = 33.5 g

Proportion:

65.0 g — 100 %

33.5 g — x

x = 51.53 %

Answer: 51.53 %.

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