Answer to Question #139139 in General Chemistry for Priyanka Mishra

Question

A 65.0g sample of mg sulfide is found to contain 31.5g of mg. What is the percent by mass of sulfur in the compound?

Answer 1

mass of sulfur = mass of MgS — mass of Mg

mass of sulfur = 65.0 g — 31.5 g = 33.5 g

$percent = \frac{mass of sulfur \times 100 }{mass of MgS}$

$persent = \frac{33.5 \times 100}{65.0} = 51.5$

Answer: 51.5 %