Question

2 g of water was heated up by 25 ̊C, the specific heat capacity of water is 4.184 J/g ̊C, how much energy was needed to heat up the water?

Answer 1

We know that;

Q=mc$\Delta$T

Where;

Q=the heat energy needed

m=mass =2g

c=specific heat capacity of water=4.184J/g/K

$\Delta$T=change in temperature=25K

Therefore, Q = 2g x 4.184Jg^-1K^-1 x 25K

Q= 209.2J