Question #133817
If 4.97 mol of C5H12 reacts with excess O2, how many moles of CO2 will be produced by the following combustion reaction?
C5H12+8O2⟶6H2O+5CO2
C5H12+8O2⟶6H2O+5CO2
Expert's answer
From the equation it is seen that from one mol of C5H12 five moles of CO2 is formed. So, the number of moles of CO2 may be found from a proportion:
x=4.97×5/1=24.85(mol).
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#340153 on Dec 2023
#340153 on Dec 2023
Comments
In the chemical Equation, C5H12+8O2⟶6H2O+5CO2 That is, 1 mole of C5H12 is reacting with 8 moles of O2 and produces 6 moles of H2O and 5 moles of CO2. So that, the amount of CO2 will be 5 times greater than the amount of C5H12. The answer is: The moles of CO2 will be produced by 4.97 moles of C5H12 = 4.97*5 = 24.85 moles