Answer to Question #133781 in General Chemistry for Rethabile Ndlovu

Question

At a certain temperature, the equilibrium constant Kc for the reaction 2BrCl(g) ⇌ Br2(g) + Cl2(g) is 0.035. A mixture of 8.00 moles of Br2 and 12.00 moles of Cl2 are placed in a 20.0 L container is allowed to come to equilibrium. What is the equilibrium concentration of BrCl?

Answer 1

2BrCl $\iff$ Br₂+Cl₂

K_c= .035

Concentration of Br₂= 8/20=.4

Concentration of Cl₂=12/20=.6

2BrCl $\iff$ Br₂+ Cl₂

Intial conc. [0] .4 .6

Change in. 2x -x -x

At equilibrium 2x .4-x .6-x

Conc.

K_c= [Br₂] [Cl₂] / [ BrCl₂]

.035= (.4-x)(.6-x)/ (2x)²

solve for x

value of x is .682

Concentration of BrCl₂= 2x=2×.682

= 1.364