H2(g) + I2(g) ⇌ 2HI(g) (1)
HI(g) ⇌ 1/2H2(g) + 1/2I2(g) (2)
Kc(1) = [HI]2 / [H2][I2]
Kc(2) = [H2]1/2[I2]1/2 / [HI]
Expressing Kc(2) by using Kc(1), we get
Kc(2) = (1/Kc(1))1/2 = (1 / 2.0*1019)1/2 = 2.2*10-10
Answer: 2.2*10-10
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