1 microliter = 1000 mL
The density of mercury "\u03c1 = 13.69\\times10^{-3}\\; g\/\u03bcL"
"m = V\\times\u03c1"
"m = 155\\; \u03bcL\\times13.69\\times10^{-3}\\; g\/\u03bcL = 2.12 \\;g"
M(Hg) = 200.6 g/mol
"n(Hg) = \\frac{m}{M} = \\frac{2.12}{200.6} = 0.01 \\;mol"
A mole of mercury atoms (with the formula Hg) contains 6.02×1023 Hg atoms.
Proportion:
1 mol – 6.02×1023 Hg atoms
0.01 mol – x
x = 6.02×1021 Hg atoms
Answer: 6.02×1021 Hg atoms
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