1 microliter = 1000 mL
The density of mercury ρ=13.69×10−3g/μL
m=V×ρ
m=155μL×13.69×10−3g/μL=2.12g
M(Hg) = 200.6 g/mol
n(Hg)=Mm=200.62.12=0.01mol
A mole of mercury atoms (with the formula Hg) contains 6.02×1023 Hg atoms.
Proportion:
1 mol – 6.02×1023 Hg atoms
0.01 mol – x
x = 6.02×1021 Hg atoms
Answer: 6.02×1021 Hg atoms
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