Question

A 200 mL solution of silver nitrate, with a concentration of 0.155 mol/L, was mixed with excess

sodium carbonate solution. The mixing of the two solutions resulting in the formation of a

white precipitate.

a) Write out the chemical equation


b) What is the precipitate


c) How many grams of precipitate should form?


d) If in actuality 3.11g of precipitate was collected, calculate the % yield.

Answer 1

a) 2AgNo3(aq)+Na2Co3(aq)-2NaNo3(aq)+Ag2Co3

b)silver carbonate Ag2Co3

c)(200/1000)×.155×(1/2)=0.0155g

d) (.0155/3.11)×100=200%