Question

A chemist starts with 0.250L of a 6.0M H2(SO4) solution. She adds water to this solution until the new volume is 0.750L. What is the molarity of this solution after she dilutes it (aka “waters it down”)?

Answer 1

C1=6M

V1=0.25L

C2=?

V2=.75

Now, C1V1=C2V2

C2=C1V1/V2

=(0.25×6)÷0.75

=2M