Answer to Question #122644 in General Chemistry for jumaan

Question

In 1.31 grams of a chloride of titanium , there is 0.528 grams of titanium. What is the emperical formula of this titanium chloride?

Answer 1

Solution.

Titanium chloride formula: TiCl_n.

n(Ti) = 0,528/48 = 0,011 mol.

_{X 0,011}

TiCl_n = Ti + nCl

^{1 1}

n(TiCl_n) = 0,011 mol.

M(TiCl_n) = m/n = 1,31/0,011 = 119 g/mol.

M(nCl) = 119 - 48 = 71 g/mol.

M(Cl) = 35,5 g/mol.

n = 2.

Formula: TiCl2.

Answer: TiCl2