Answer to Question #116138 in General Chemistry for Chelse Bell

Question

A mass of gas occupies 1.00 L at 100 kPa. At what pressure does this gas
occupy
a) 2.00 litres,
b) 0.500 litres?

Answer 1

P₁ = 100 kPa

V₁ = 1.00 L

Solution:

The relationship for Boyle’s Law can be expressed as follows:

P₁V₁ = P₂V₂,

where P₁ and V₁ are the initial pressure and volume values, and P₂ and V₂ are the values of the pressure and volume of the gas after change.

a) V₂ = 2.00 L

Thus:

P₂ = P₁V₁/V₂

P₂ = (100 kPa × 1.00 L) / (2.00 L) = 50 kPa

Answer (a): P₂ = 50 kPa.

b) V₂ = 0.50 L

Thus:

P₂ = P₁V₁/V₂

P₂ = (100 kPa × 1.00 L) / (0.50 L) = 200 kPa

Answer (b): P₂ = 200 kPa.