Answer to Question #116136 in General Chemistry for Chelse Bell

Question

A student collects 25.0 mL of gas at 96.0 kPa. What volume would this gas
occupy at 101.325 kPa. There is no change in temperature or mass.

Answer 1

According to Boyle's law (P₁V₁ = P₂V₂, T=const) it is possible to calculate volume of gas after changing of pressure:

25.0 mL * 96.0 kPa = 101.325 kPa * V₂

V₂ = (25.0 mL * 96.0 kPa)/101.325 kPa = 23.7 mL

Answer: The volume of gas is 23.7 mL