Question #116131
If 22.0 L of oxygen at 128 kPa is allowed to expand at constant temperature
until its pressure is 101.3 kPa, how much larger will the volume become?
1
Expert's answer
2020-05-19T08:44:57-0400

PV=constantPV=constant

P1V1=P2V2P_1V_1=P_2V_2

22×128=101.3×V222\times128=101.3\times V_2

V2=27.8LV_2=27.8 L


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