P1=104.66 KPa;V1=525 mlP_1=104.66 \ KPa;V_1=525\ mlP1=104.66 KPa;V1=525 ml ;
P2=99.33 KPa;V2=?P_2=99.33\ K Pa;V_2=?P2=99.33 KPa;V2=?
Using Boyle's law,
P1V1=P2V2 ⟹ 104.66×525=99.33×V2 ⟹ V2=553.17 mlP_1V_1=P_2V_2\implies 104.66\times 525=99.33\times V_2\implies V_2=553.17\ mlP1V1=P2V2⟹104.66×525=99.33×V2⟹V2=553.17 ml
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