Question

Use stoichiometry to determine how much sodium acetate (in grams) we should produce by reacting 0.05 moles of sodium bicarbonate/baking soda. HINT: The molar mass calculated in the previous problem might be useful.

Answer 1

$CH_3COOH+NaHCO_3 \to CH_3COONa + H_2O+CO_2$

1 mole of baking soda/sodium bicarbonate produces 1 mole of Sodium Acetate.

0.05 mole of baking soda/sodium bicarbonate produces 0.05 mole of Sodium Acetate.

Molar mass of Sodium Acetate is 82 gms.

Thus, amount of sodium acetate produced $=0.05*82=4.1 gms.$