Answer to Question #115481 in General Chemistry for Trevor

Question

A stock solution of CuCl2 was made by adding 510g of solute to 0.95L of water. What volume of stock solution would you use to create 14.1L of 0.58M CuCl2 solution? Round your answer to the nearest 0.1L.

Answer 1

n1(CuCl2)=m(CuCl2)/Mr(CuCl2)=510/135=3,78 moll

C1=n1/v1=3,78/0,95=3,98 moll/L

C1*V1=C2*V2

3,98*x=0,58*14,1

x=2,05477=> 2,1 liter