[H+][OH−]=10−14[H^+][OH^-]=10^{-14}[H+][OH−]=10−14
[H+]=10−14[OH−][H^+]=\frac{10^{-14}}{[OH^-]}[H+]=[OH−]10−14
pH=-log[H+]
1) [OH-] =3.5×10−53.5\times10^{-5}3.5×10−5
[H+]=10−143.5×10−5\frac{10^{-14 }}{3.5\times10^{-5}}3.5×10−510−14=2.85×\times×10-10
pH=-log[2.85×\times×10-10] = 10-0.45 =9.55
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