"[H^+][OH^-]=10^{-14}"
"[H^+]=\\frac{10^{-14}}{[OH^-]}"
pH=-log[H+]
1) [OH-] ="3.5\\times10^{-5}"
[H+]="\\frac{10^{-14\n\n\n\n\n}}{3.5\\times10^{-5}}"=2.85"\\times"10-10
pH=-log[2.85"\\times"10-10] = 10-0.45 =9.55
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